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Byju's Answer
Standard XII
Mathematics
Slope Intercept Form of a Line
1. Find the c...
Question
1. Find the co-ordinate of foot of perpendicular far the point (-1,3) is the line 3x+4y-16=0
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Solution
Dear student
The
line
3
x
+
4
y
-
16
=
0
can
be
rearranged
as
4
y
=
-
3
x
+
16
⇒
y
=
-
3
4
x
+
4
Comparing
this
with
the
standard
equation
line
y
=
mx
+
c
where
m
is
the
slope
of
the
line
and
c
is
the
intercept
on
y
axis
slope
of
the
line
=
-
3
4
Thus
slope
of
the
line
perpendicular
to
the
given
line
would
be
-
1
m
=
-
1
-
3
4
=
4
3
Equation
of
the
perpendicular
line
would
be
of
the
form
y
=
mx
+
c
where
m
=
4
3
thus
,
y
=
4
3
x
+
c
1
is
the
equation
of
the
line
perpendicular
to
the
line
3
x
+
4
y
-
16
=
0
As
the
line
passes
through
the
point
-
1
,
3
substituting
x
=
-
1
and
y
=
3
in
1
3
=
4
3
-
1
+
c
c
=
13
3
The
equation
of
the
line
perpendicular
to
the
line
3
x
+
4
y
-
16
=
0
from
the
-
1
,
3
i
y
=
4
3
x
+
13
3
3
y
-
4
x
-
13
=
0
Regards
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0
Similar questions
Q.
Find the coordinates of the foot of perpendicular from the point
(
−
1
,
3
)
to the line
3
x
−
4
y
−
16
=
0
Q.
The co-ordinates of foot of the perpendicular drawn on line
3
x
−
4
y
−
5
=
0
from the point
(
0
,
5
)
is
Q.
The co-ordinates of the foot of the perpendicular from
(
2
,
3
)
to the line
3
x
+
4
y
−
6
=
0
are :
Q.
Find the co-ordinates of the foot of perpendicular drawn from the point
A
(
−
1
,
8
,
4
)
to the line joining the points
B
(
0
,
–
1
,
3
)
and
C
(
2
,
–
3
,
–
1
)
.
Q.
A perpendicular is drawn from the point
A
(
1
,
8
,
4
)
to the line joining the points
B
(
0
,
−
1
,
3
)
and
C
(
2
,
−
3
,
−
1
)
. The co-ordinates of the foot of the perpendicular is:
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