Question

(1) Find the moment of force of 20 N about an axis of rotation at a distance 0.5 m from the force.

(2) A spanner of length 10 cm is used to open a nut by applying a minimum force of 5 N. Calculate the moment to force required.

Answer 1

(1) Moment of force means torque.

$\tau =force\times \perp dis\tan ce$

$\tau =20\times 0.5$

$\tau =10N-m$

(2) $\tau =force\times dis\tan ce$

$\tau =5\times \frac{10}{100}$

$\tau =0.5N-m$