$1 g H_{2}$ gas STP is expanded so that the volume is doubled. Hence, work done is:

11.2 L - a t m

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2.4 L - a t m

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22.4 L - a t m

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None of these

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Solution

The correct option is A $11.2 L - a t m$
As we know,

2gm hydrogen has a volume of 22.4 lit at STP.

$V_{1} (v o l u m e o f 1 g H_{2}) = 11.2 L$ at STP.
$V_{2} (v o l u m e o f 1 g H_{2}) = 22.4 L$

Therefore, the work done is:

$∴ W = P Δ V = 1 \times (22.4 - 11.2) = 11.2 L - a t m$

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