Question

$1g$ of ice at $0^{0}C$ is converted to steam at ${100}^{0}C$. The amount of heat required will be:

($L_{steam}=536cal/g$)

• A. $756cal$
• B. $12000cal$
• C. $716cal$
• D. $450cal$

Answer 1

The correct option is C $716cal$

Total Heat required $=$ Heat to transform ($0^o$C ice to 0${}^o$C water+0${}^o$C water to 100${}^o$C water+100${}^o$C water to 100${}^o$C steam)
$=1[80+1(100-0)+536]=716cal$