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Question

1 g of Mg atom in the vapour phase absorbs 500 kJ of energy. Find the composition of Mg formed as a result of absorption of energy. IE1 and IE2 for Mg are 740 and 1450 kJ /mol respectively.

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Solution

1g of Mg=124=4.167×102mol
energy used in ionizing Mg to Mg+=4.167×102mol×740=30.84kJ
Energy used in ionizing Mg+ to Mg2+=(5030.84)=19.16kJ
Amount of Mg+ converted to Mg2+=19.161450=1.321×102mol
Amount of Mg+ remaining as such= 4.167×1021.321×102
=2.846×102mol
Composition of final mixture,
% of Mg+=2.846×1024.167×102×100
=68.3
% of Mg2+=10068.3=31.7

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