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Internal Energy

1g of water n...

Question

$1$ g of water needs $4.2$ J and $100$ g of water needs $420$ j of heat energy, respectively so as to rise their temperature by $1^{o} C$ . Calculate the heat capacity the heat capacity of water in both cases.

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Solution

Heat required $H = m S Δ T$
Case (1) : $H = 4.2 J$ $m = 1 g = 10^{- 3} k g$ $Δ T = 1^{o} C$
Or $4.2 = 10^{- 3} \times S \times 1$ $⟹ S = 4200 J / k g /^{o} C$
Case (1) : $H = 420 J$ $m = 100 g = 10^{- 1} k g$ $Δ T = 1^{o} C$
Or $420 = 10^{- 1} \times S \times 1$ $⟹ S = 4200 J / k g /^{o} C$

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75 g

10^{o} C

25200 J

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- 10^{o} C

100^{o} C

= 2.1 J g^{- 1} K^{- 1}

= 4.2 J g^{- 1} K^{- 1}

= 336 J g^{- 1}

20^{\circ} C

72^{\circ} C

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300 g

40 ° C

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= 4.2 J g^{- 1} K^{- 1}

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