Question

What will be the supply voltage if three resistors of $4\Omega$ each are connected in series in a circuit carrying $4A$ of current?

Answer 1

Step 1: Given Data

Number of resistors $=3$

Resistance of each resistor $R=4\Omega$

Current through the circuit $I=4A$

Step 2: Equivalent Resistance

We know that the equivalent resistance in series is given as,

$R_{eq}=R_1+R_2+R_3+.....$

Given that all the resistors have equal resistances.

$\therefore R_{eq}=3\times R$

$=3\times 4=12\Omega$

Step 3: Calculate the Voltage

According to Ohm's law,

$V=I{R}_{eq}$

Upon substituting the values we get,

$V=12\times 4$

$=48V$

Hence, the supply voltage of the given circuit is $48V$.