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Question

1 . Is external force always necessary for work to be done ?
2. Why is work done by a varying force
during a round trip not necessarily zero?
3. The position (x) of a particle of mass 1kg moving along x-axis at time t is given by (x=1by 2 t2) metre. Find the work done by force acting on it in time interval from t=0 to t=3s.

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Solution

1. Workdone W = F S cosθ.If External force F=0 then W=0 because internal force does count to workdone.2. Workdone by variable force for the round may or may not be zero. It depends onthe resultant force. In case resultant force of variable forces is zero then workdone by variable force is zero and on the other hand if resultant force is non zero then workdoneby variable force is also non zero.3. x= 12t2 ..... (i)dxdt=-22t3 and d2xdt2=a=--3t4=3t4from (i),t2=12xt4=14x2a=12x2Therefore, W = 03Fdx=03ma dx=031×12x2 dxW=123x303 JW=4×27=108 J

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