Negative Work
Trending Questions
What should be the angle between force and the displacement for maximum and minimum work?
In a tug of war one team gives way to the other what work is being done and by whom
A force of displaces a body by , the angle between force and displacement is , then find the work done.
A man carrying a bucket of water, walking on a level road with a uniform velocity does no work.
- True
- False
- 1:2
- 1:1
- 2:1
- 4:1
In tug of war, the team that exerts a larger tangential force on the ground wins. Consider the period in which a team is dragging the opposite team by applying a larger tangential force on the ground. List which of the following works are negative?
i.Work by the winning team on the losing team
ii.Work by the losing team on the winning team
iii.Work by the ground on the winning team
iv.Work by the ground on the losing team
ii, iii, iv
I, ii, iii, iv
None of these
ii, iv
- W1=mgh, W2=mgh
- W1=mgh, W2=−mgh
- W1=−mgh, W2=mgh
- W1=−mgh, W2=−mgh
If the angle between force F and displacement s is 60o , then the work done is,
Fs
F/s
F X s/2
2 Fs
- 12kgm2s−1
- 6.0kgm2s−1
- 4.5kgm2s−1
- 8.0kgm2s−1
- 1:2
- 1:1
- 2:1
- 4:1
- W1=mgh, W2=mgh
- W1=mgh, W2=−mgh
- W1=−mgh, W2=mgh
- W1=−mgh, W2=−mgh
- positive
- negative
- zero
- can't be said.
Reason: Force and displacement are in opposite directions.
- Both Assertion and Reason are true but Reason is not the correct explanation of Assertion
- Assertion is true but the Reason is false
- Both Assertion and Reason are true and the Reason is correct explanation of Assertion
- Assertion is false but the Reason is true
- 20 cm
- 30 cm
- 10 cm
- 4 cm
- 100√3
- 500√3
- 250√3
- 250
If force is applied at an angle to the direction of displacement of a body, how will you derive the amount of work done?
What should be the angle between the direction of force and direction of displacement if
- Work done is zero and
- Work done is negative?
A person pulls a body on a horizontal surface by applying a force of 5.0 N at an angle of 30o, with the horizontal. Find the work done by this force in displacing the body through 2.0 m.
- 12π ⎷k1a2+k2b2L2(m+M3)
- 12π√k2+k1M+m
- 12π ⎷k2+k1a2b24M3+m
- 12π ⎷k1+k2b2a243m+M
- False
- True
- Equal to both
- Greater for the longer part
- Greater for the shorter part
- Data insufficient
The applied force F is enough to move, both block A and B together.The frictional force between A nad B does ________ work on A and _________ work on B.
- positive, positive
- positive, negative
- negative, negative
- negative, positive
- Fcosθ
- μmg
- μmg√1+μ2
- All of these
- True
- False
- W(1+ag)
- W
- W(1−ag)
- W(1−a2g2)