Question

A person pulls a body on a horizontal surface by applying a force of 5.0 N at an angle of 30^o, with the horizontal. Find the work done by this force in displacing the body through 2.0 m.

• A. $5\sqrt{3}J$
• B. $6\sqrt{2}J$
• C. $7\sqrt{3}J$
• D. $4\sqrt{3}J$

Answer 1

The correct option is A

$5\sqrt{3}J$

Step 1: Given data

Force F = 5 N

Displacement s = 2 m

angle between force and direction of displacement $\theta$ = 30^o

Step 2: Calculation for work done:

$$\begin{gathered} workdone=force\times displacement\times \cos \theta \\ =f\times s\times \cos \theta \\ =5N\times 2m\times \cos 30° \\ =10\times \frac{\sqrt{3}}{2} \\ =5\sqrt{3}J \end{gathered}$$

Hence option(A) is correct.