Question

If the angle between force F and displacement s is 60^o , then the work done is,

• A. Fs
• B. F/s
• C. F X s/2
• D. 2 Fs

Answer 1

The correct option is C

F X s/2

Step 1: Given data

Let Force be = F

Let Displacement be = s

The angle between the force and direction of displacement, $\theta$=60

Step 2: Calculation

Work done when a force is applied at a certain angle with the direction of displacement,

$$\begin{gathered} W=force\times displacement\times \cos \theta \\ =F\times s\times \cos 60 \\ =F\times s\times \frac{1}{2} \\ =F\times \frac{s}{2} \end{gathered}$$

Where $\theta$ is the angle between force and direction of displacement

Hence option (C) is the correct answer.