1 kg piece of copper is drawn into a wire of $1 m m^{2}$ cross-section, and another 1 kg copper piece into a wire of $2 m m^{2}$ cross-section. Compare the resistance of these wires.

2:1

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4:1

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8:1

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16:1

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Solution

The correct option is B
4:1

The volume of wire = length x Cross-sectional Area.

Since volume is same in both the cases, the length of second wire will be half of the length of 1st wire.

Using R = $\frac{ρ L}{A}$ , we get the resistance of the 1st wire is 4 times the value of resistance of the 2nd wire.

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1 kg piece of copper is drawn into a wire of 1 mm2 cross-section, and another 1 kg copper piece into a wire of 2 mm2 cross-section. Compare the resistance of these wires.

The correct option is B 4:1 The volume of wire = length x Cross-sectional Area. Since volume is same in both the cases, the length of second wire will be half of the length of 1st wire. Using R = ρLA, we get the resistance of the 1st wire is 4 times the value of resistance of the 2nd wire.

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