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Question

1 L of a mixture of CO and CO2 is passed through red hot charcoal in a tube. The new volume becomes 1.4 L. Find out percentage composition of mixture by volume. All measurements are made at constant temperature and pressure.

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Solution

Let x L be volume of CO, then volume of CO2=(1x)L.
C+CO22CO
(1x)L CO2 reacts with C.
Final volume will be x+(1x)+(1x)=1.6x=0.4LCO
Volume of CO2=0.6L

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