Question

1 L solution containing 49 g of sulphuric acid is diluted to 10 L by adding water. What is the normality of the resultant solution?

• A. 0.1 N
• B. 1.0 N
• C. 0.5 N
• D. 5.0 N

Answer 1

The correct option is A 0.1 N

Number of gram-equivalents of $H_{2}S{O}_4$
= $\frac{\text{Given mass}}{\text{equivalent mass}}$ = $\frac{49}{49}=1\text{Normality}=\frac{\text{gram equivalents}}{\text{volume of solution in L}}=\frac{1}{1}=1N$
As $N_1{V}_1=N_2{V}_{2}1\times 1=N_2\times 10N_2=0.1N$