Question

1 L solution containing 490 g of sulphuric acid is diluted to 10 L with water. What is the normality of the resulting solution?

• A. 1.00 N
• B. 0.55 N
• C. 0.26 N
• D. 0.86 N

Answer 1

The correct option is A 1.00 N

Gram equivalent of $H_{2}S{O}_4=\frac{\text{given mass}}{\text{equivalent mass}}=\frac{490}{49}=10$

$\text{Normality}=\frac{\text{gram equivalent of solute}}{\text{total volume of solution (L)}}=\frac{10}{1}N$
1 L of 10 N solution is diluted to 10 L.

$N_i{V}_i=N_f{V}_f\Rightarrow (10\times 1)=(N_f\times 10)$
$N_f=1N$