Question

1 L solution containing 490 g of sulphuric acid is diluted to 10 L with water. What is the normality of the resultant solution?

• A. 1.0 N
• B. 10.0 N
• C. 0.5 N
• D. 5.0 N

Answer 1

The correct option is A 1.0 N

$\text{Normality}=\frac{\text{number of equivalents of solute}}{\text{Volume of the solution in L}}=\frac{\frac{\text{given mass}}{\text{Equivalent mass}}}{\text{Volume (in L)}}$
$N_1{V}_1=N_2{V}_2$
Where,
$N_1\Rightarrow$Normality of the initial solution $=\frac{490}{49}$ N
$V_1\Rightarrow$ Volume of the initial solution = 1 L
$N_2\Rightarrow$ Normality of the final solution
$V_2\Rightarrow$Volume of the final solution = 10 L
$\frac{490}{49}\times 1=N_2\times 10$
$N_2=\frac{490}{49\times 10}$ = 1 N