1 litre mixture of $C O$ and $C O_{2}$ is taken. This is passed through a tube containing red-hot charcoal. The volume now becomes 1.6 liters. The volumes. are measured under the same conditions. Find the composition of the mixture by volume.

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Solution

Let there be $x$ mL $C O$ in the mixture, hence, there will be:
$(1000 x) m L C O_{2}$ . The reaction of $C O_{2}$ with red hot charcoal may be given as:
$C O_{2} (g) 1 v o l . (1000 - x) + C (s) \to 2 C O (g) 2 v o l . 2 (1000 x)$
Total volume of the gas becomes $= x + 2 (1000 - x)$
$x + 2000 - 2 x = 1600$
$x = 400 m L$
$∴$ Volume of $C O = 400 m L$ and volume of $C O_{2} = 600 m L$

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