1 litre of mixture of $C O$ and $C O_{2}$ is taken. The mixture is passed through a tube containing red hot charcoal. The volume now becomes 1.6 litre. The volumes are measured under the same conditions. The volume of $C O_{2}$ in the original mixture is

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Solution

Following reaction takes places in tube,

$C + C O_{2} \to 2 C O$
The volumes are measured under the same conditions. They must be in the whole number ratio accroding to Dalton's law
Volume of mixture of $C O a n d C O_{2}$ = 1L

Let volume of $C O_{2}$ in mixture = x

Volume of CO formed from the reaction = 2 x
Volume of CO before the reaction = 1 – x
After the reaction , the mixture does not contain $C O_{2}$
Total volume of CO after reaction $= (1 - x) + 2 x = 1 + x = 1.6$
x = 0.6 L

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