Question

$1$ mol of ferric oxalate is oxidised completely by $x$ mol of $Mn{O}_4^{-}$ in acidic medium. Then, $x$ is :

• A. $1.2$
• B. $1.6$
• C. $1.8$
• D. $1.5$

Answer 1

The correct option is A $1.2$

The reaction involved is shown below:
$F{e}_2(C_2{O}_4{)}_3\to 2F{e}^{3+}+3C_2{O}_4^{2-}$
$3(C^{3+}{)}_2\to 6C^{4+}+6e^{-}$
$M{n}^{7+}+5e^{-}\to M{n}^{2+}$
$6$ mol of $M{n}^{7+}$ needs $15$ mol of $C_2{O}_4^{2-}$ or $5$ mol of $F{e}_2(C_2{O}_4{)}_3$.
Therefore, $1$ mol will require $\frac{6}{5}$ $=$ $1.2$.