Question

$1$ mole of $Mn{O}_4^{-}$ will oxidise $x$ moles of ferric oxalate in acidic medium, $x$ is :

• A. $\frac{5}{6}$
• B. $\frac{6}{5}$
• C. $5$
• D. $6$

Answer 1

The correct option is A $\frac{5}{6}$

In acidic medium,
$Mn{O}_4^{-}\to M{n}^{+2}$

It will oxidise the only oxalate $(C_2{O}_4^{2-}$) as ferric is already in highest oxidised state.

The reaction is as follows:

${Fe}_2{\left(C_2{O}_4\right)}_3\rightleftharpoons 2{Fe}^{3+}+3C_2{O}_4^{2-}$

At the equivalent point, both reactant have the same number of equivalents.

So, one mole of $Mn{O}_4^{-}$ will oxidise $\frac{5}{6}$ mole of ferric oxalate.