1 mol of iron Fe reacts completely with 0-65 mol of O 2 to give a mixture of only FeO and Fe 2 O 3 - mole ratio of ferrous oxide to ferric oxide is Give the solution using some short cut method

2Fe + O2 == gt; 2FeO a a/2 moles a 4Fe +3O2 === gt; 2Fe2O3 b 3b/4 moles b/2 a+ b = 1 a/2 + 3b/4 = 0.65 or 1/2 a+ 1/2 b = 1/2 ( I substitute the firs ...

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Standard XII

Chemistry

Electrometallurgy

1 mol of iron...

Question

1 mol of iron( Fe) reacts completely with 0.65 mol of O₂ to give a mixture of only FeO and Fe₂O₃ . mole ratio of ferrous oxide to ferric oxide is

Give the solution using some short cut method

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Solution

2Fe + O2 ==> 2FeO
a a/2 moles a
4Fe +3O2 ===> 2Fe2O3
b 3b/4 moles b/2

a+ b = 1
a/2 + 3b/4 = 0.65

or 1/2 a+ 1/2 b = 1/2 ( I substitute the first equation with 1/2)
a/2 + 3b/4 = 0.65
==> b = 0.6 moles
a= 0.4 moles
--> moles FeO = 0.4 moles
moles Fe2O3 = 0.6/2 = 0.3 moles
===> Ratio = 0.4/0.3 = 4/3

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Similar questions

1 m o l

of iron

(F e)

reacts competely with

0.65 m o l O_{2}

to give a mixture of only

F e O

and

F e_{2} O_{3}

. Mole ratio ferrous oxide to ferric oxide to ferric oxide is:

Q. 1.0 mol of Fe reacts completely with 0.65 mol of

O_{2}

to give a mixture of only

F e O

and

F e_{2} O_{3}

. The mole ratio of ferrous oxide to ferric oxide is

1.0

mol of Fe reacts completely with

0.65

mol of

O_{2}

to give a mixture of only

F e O

and

F e_{2} O_{3} .

The mole ratio of ferrous oxide to ferric oxide is:

Q. 1.0 mole of

F e

reacts completely with 0.65 mole of

O_{2}

to give a mixture of only

F e O

and

F e_{2} O_{3}

.
The mole ratio of ferrous oxide to ferric oxide is x: y, then (x+y) is

Q. 1.0 mole of

F e

reacts completely with 0.65 mole of

O_{2}

to give a mixture of only

F e O

and

F e_{2} O_{3}

.
The mole ratio of ferrous oxide to ferric oxide is x: y, then (x+y) is

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1 mol of iron( Fe) reacts completely with 0.65 mol of O2 to give a mixture of only FeO and Fe2O3 . mole ratio of ferrous oxide to ferric oxide is Give the solution using some short cut method

2Fe + O2 ==> 2FeO a a/2 moles a 4Fe +3O2 ===> 2Fe2O3 b 3b/4 moles b/2 a+ b = 1 a/2 + 3b/4 = 0.65 or 1/2 a+ 1/2 b = 1/2 ( I substitute the first equation with 1/2) a/2 + 3b/4 = 0.65 ==> b = 0.6 moles a= 0.4 moles --> moles FeO = 0.4 moles moles Fe2O3 = 0.6/2 = 0.3 moles ===> Ratio = 0.4/0.3 = 4/3

1 mol of iron( Fe) reacts completely with 0.65 mol of O₂ to give a mixture of only FeO and Fe₂O₃ . mole ratio of ferrous oxide to ferric oxide is

Give the solution using some short cut method

2Fe + O2 ==> 2FeO
a a/2 moles a
4Fe +3O2 ===> 2Fe2O3
b 3b/4 moles b/2

a+ b = 1
a/2 + 3b/4 = 0.65

or 1/2 a+ 1/2 b = 1/2 ( I substitute the first equation with 1/2)
a/2 + 3b/4 = 0.65
==> b = 0.6 moles
a= 0.4 moles
--> moles FeO = 0.4 moles
moles Fe2O3 = 0.6/2 = 0.3 moles
===> Ratio = 0.4/0.3 = 4/3