1 mole each of $A g N O_{3}, C u S O_{4}$ and $A l C l_{3}$ is electrolysed. Number of faradays required are in the ratio of :

1 : 1 : 1

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1 : 2 : 3

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3 : 2 : 1

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1 : 3 : 1

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Solution

The correct option is B 1 : 2 : 3
$A g^{+} + e^{-} ⟶ A g$

$C u^{2 +} + 2 e^{-} ⟶ C u$

$A l^{3 +} + 3 e^{-} ⟶ A l$

Thus, number of faradays required by $1 m o l$ each of $A g^{+}, C u^{2 +}$ and $A l^{3 +} = 1 : 2 : 3$

Hence, the correct option is $B$

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A g N O_{3}, C u S O_{4}

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1

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C r^{3 +}

M n O_{4}^{-}

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