1 mol each of $A g N O_{3}, C u S O_{4}$ and $A l C l_{3}$ are electrolysed. Number of faradays required per mole of each are in the ratio of :

1 : 1 : 1

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1 : 2 : 3

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3 : 2 : 1

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1 : 3 : 1

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Solution

The correct option is B 1 : 2 : 3
$A g^{+} + e^{-} \to A g$

$C u^{2 +} + 2 e^{-} \to C u$

$A l^{3 +} + 3 e^{-} \to A l$

Thus, number of faradays required by 1 mol each = 1 : 2 : 3.

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