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Faraday's First Law

1 mole electr...

Question

1 mole electron are passed through CuSO₄, AgNO₃, and AlCl₃,. What will be the mole ratio of Cu, Ag, Al collected at the electrodes?

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Solution

According to Faraday's second law
Weight Deposited=(Electrochemical Equivalent)CurrentTime

Electrochemical Equivalent = Molecular weight/{(n)*96500}
Hence,
1/2 mole of Cu, 1 mole of Ag and 1/3 mole of Al will be deposited

Therefore, 3:6:2 will be the mole ratio.

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