1 mole of Benzene (P∘Benzene=42mm Hg) and 2 mole of toluene (P∘toluene=36mm Hg) will have
A
Positive deviation from Raoult’s law.
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B
Negative deviation from Raoult’s law.
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C
Total vapour pressure 38mm Hg
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D
Mole fraction of vapour of toluene above liquid mixture is 12/19.
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Solution
The correct options are C Total vapour pressure 38mm Hg D Mole fraction of vapour of toluene above liquid mixture is 12/19. Benzene & Toluene form ideal solution Psolution=P0BXB+P0TXT
=[42(13+36(23))]
=14+24=38mm Hg
Mole fraction of toluene in the vapor phase YT=P0TXTPT=2438=1219