Question

$1$ mole of $Mn{O}_4^{-}$ will oxidise $\frac{x}{6}$ moles of ferric oxalate in acidic medium, $x$ is _________.

Answer 1

In acidic medium,
$Mn{O}_4^{-}\to M{n}^{+2}$

It will oxidise only oxalate $(C_2{O}_4^{2-}$) as ferric is already in the highest oxidised state.

The reaction is as follows:
${Fe}_2{\left(C_2{O}_4\right)}_3\rightleftharpoons 2{Fe}^{3+}+3C_2{O}_4^{2-}$

At equivalent point, both reactant have same number of equivalents.

So, one mole of $Mn{O}_4^{-}$ will oxidise $\frac{5}{6}$ moles of ferric oxalate.

Therefore, the value of $x$ is 5.