1 mole of MnO2-4 in neutral aqueous medium disproportionates to-

The correct option is A 2/3 mole of MnO^ _4 and 1/3 mole of MnO_2 .The oxidation state of Mn in MnO^2 _4 , MnO^ _4 and M ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Potassium Permanganate

1 mole of M...

Question

$1$ mole of $M n O_{4}^{2 -}$ in neutral aqueous medium disproportionates to:

\frac{2}{3}

mole of

M n O_{4}^{-}

and

\frac{1}{3}

mole of

M n O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{3}

mole of

M n O_{4}^{-}

and

\frac{2}{3}

mole of

M n O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

mole of

M n_{2} O_{7}

and

\frac{1}{3}

mole of

M n O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{3}

mole of

M n_{2} O_{7}

and

\frac{1}{3}

mole of

M n O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{2}{3}$ mole of $M n O_{4}^{-}$ and $\frac{1}{3}$ mole of $M n O_{2}$ .
The oxidation state of Mn in $M n O_{4}^{2 -}$ , $M n O_{4}^{-}$ and $M n O_{2}$ are +6, +7 and +4 respectively.
$M n^{6 +} \to M n^{7 +} + 1 e^{-}$
$M n^{6 +} + 2 e^{-} \to M n^{4 +}$

To balance the number of electrons, oxidation half reaction is multiplied with 2 and added to reduction half reaction.
$∴ 3 M n O_{4}^{2 -} \to 2 M n O_{4}^{-} + M n O_{2}$
1 mole of $M n O_{4}^{2 -}$ in neutral aqueous medium disproportionates to $\frac{2}{3}$ mole of $M n O_{4}^{-}$ and $\frac{1}{3}$ mole of $M n O_{2}$

Suggest Corrections

Similar questions

M n O_{4}^{2 -}

(1 mole) in neutral aqueous medium is disproportionate to:

M n O_{2} + 4 H C l ⟶ M n C l_{2} + 2 H_{2} O + C l_{2}

2

moles

M n O_{2}

reacts with

4

moles of

H C l

to form

11.2

C l_{2}

at STP. Thus, percent yield of

C l_{2}

is:

How much charge is required for the following reductions :

(i) 1 mole of $A l^{3 +}$ to Al ?

(ii) 1 mole of $C u^{2 +}$ to Cu ?

(iii) 1 mole of $M n O_{4}^{-} t o M n^{2 +}$ ?

Q. 1 mole of

B a (O H)_{2}

will exactly neutralize

Q. For a reaction

M^{x +} + M n O_{4}^{-} \to M O_{3}^{-} + M n^{2 +} + \frac{1}{2} O_{2}

If 1 mole of

M n O_{4}^{-}

oxidises 1.66 moles of

M^{x +}

M O_{3}^{-}

, then the value of x in the reaction is

Join BYJU'S Learning Program

1 mole of MnO2−4 in neutral aqueous medium disproportionates to:

$1$ mole of $M n O_{4}^{2 -}$ in neutral aqueous medium disproportionates to: