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Characteristics of Chemical Equilibrium

1 mole of P...

Question

1 mole of $P C l_{3}$ and 1 mole of $P C l_{5}$ is taken in a vessel of 10 L capacity maintained at 400 K.At equilibrium, the moles of $C l_{2}$ is found to be $4 \times 10^{- 3}$

K_{c}

for the reaction :

P C l_{5} (g)

⇌

P C l_{3} (g) + C l_{2} (g)

4 \times 10^{- 4}

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K_{p}

for the reaction :

P C l_{3} + C l_{2} (g)

⇌

P C l_{5} (g) + (g)

4 \times 10^{- 4} \times (0.082 \times 400)

atm

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P C l_{3} (g)

is added to the equilibrium mixture,

K_{p}

at the new equilibrium becomes greater than the

K_{p}

at old equilibrium.

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After equilibrium is achieved, moles of

P C l_{3}

is doubled and moles of

C l_{2}

is halved simultaneously then the partial pressure of

P C l_{5}

remains unchanged.

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Solution

The correct options are
A $K_{c}$ for the reaction : $P C l_{5} (g)$ $⇌$ $P C l_{3} (g) + C l_{2} (g)$ is $4 \times 10^{- 4}$ M.
B $K_{p}$ for the reaction : $P C l_{3} + C l_{2} (g)$ $⇌$ $P C l_{5} (g) + (g)$ is $4 \times 10^{- 4} \times (0.082 \times 400)$ atm
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Similar questions

Q. For the given reaction,

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

Calculate

K_{p}

, if at equilibrium

2

moles each of

P C l_{5}, P C l_{3},

and

C l_{2}

is maintained at

250^{o} C

and a total pressure of

3 atm

Q. For the reaction

P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g),

The mole of each component

P C l_{5}, P C l_{3} a n d C l_{2}

at equilibrium were found to be 2. If the total pressure is 3 atm. The value of

K_{P}

will be-

Q. A quantity of

P C l_{5}

was heated in a 10 litre vessel as

250^{o} C; P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}

. At equilibrium the vessel contains 0.1 mole of

P C l_{5}

. 0.20 mole of

P C l_{3}

and 0.2 mole of

C l_{2}

. The equilibrium constant of the reaction is:

Q. An equilibrium mixture of

P {C l}_{5}, P {C l}_{3}

and

{C l}_{2}

at a certain temperature contians

0.5 \times 10^{- 3} M

P {C l}_{3}

1.5 \times 10^{- 2}

P {C l}_{3}

and

3 \times 10^{- 2} M

{C l}_{2}

. Calculate the equilibrium constant

K_{c}

for the reaction

P {C l}_{5} (g) ⇌ P {C l}_{3} (g) + {C l}_{2} (g)

Q. A quantity of

P C l_{5}

was heated in a 10 litre vessel at

250^{\circ} C

P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}

.
At equilibrium, the vessel contains 0.1 mole of

P C l_{5}

, 0.2 mole of

P C l_{3}

and 0.2 mole of

C l_{2}

. The equilibrium constant is :

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1 mole of PCl3 and 1 mole of PCl5 is taken in a vessel of 10 L capacity maintained at 400 K.At equilibrium, the moles of Cl2 is found to be 4×10−3

The correct options are A Kc for the reaction : PCl5(g)⇌PCl3(g)+Cl2(g) is 4×10−4 M. B Kp for the reaction : PCl3+Cl2(g)⇌PCl5(g)+(g) is 4×10−4×(0.082×400) atmundefined

1 mole of $P C l_{3}$ and 1 mole of $P C l_{5}$ is taken in a vessel of 10 L capacity maintained at 400 K.At equilibrium, the moles of $C l_{2}$ is found to be $4 \times 10^{- 3}$

The correct options are
A $K_{c}$ for the reaction : $P C l_{5} (g)$ $⇌$ $P C l_{3} (g) + C l_{2} (g)$ is $4 \times 10^{- 4}$ M.
B $K_{p}$ for the reaction : $P C l_{3} + C l_{2} (g)$ $⇌$ $P C l_{5} (g) + (g)$ is $4 \times 10^{- 4} \times (0.082 \times 400)$ atm
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