Question

$1$ mole of real gas $(a=1.4)$ occupies a volume of $0.1\text{L}$ at $300\text{K}$, then what will be the pressure of gas?

• A. $2460\text{atm}$
• B. $2320\text{atm}$
• C. $106\text{atm}$
• D. $212\text{atm}$

Answer 1

The correct option is C $106\text{atm}$

We know that,
$(P+\frac{a{n}^2}{V^2})\left(V\right)=nRT$ (Neglecting $b$).

$\Rightarrow P+\frac{1.4\times 1^2}{{0.1}^2}=\frac{1\times 0.0821\times 300}{0.1}$
($\because R=0.0821\text{atm-L/mol-K}$)
$\Rightarrow P=106\text{atm}$