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Ideal Gas Equation

If two moles ...

Question

If two moles of an ideal gas at $500 K$ occupies a volume of $41 L$ , the pressure of the gas is :

$(R = 0.082 L a t m K^{- 1} m o l^{- 1})$

A

2 a t m

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B

3 a t m

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C

4 a t m

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D

5 a t m

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E

1 a t m

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Solution

The correct option is A $2 a t m$
Ideal gas equation is :

$p V = n R T$

$∴ p = \frac{n R T}{V} = \frac{2 \times 0.082 \times 500}{41}$
$= 2 a t m$

Hence the correct option is A.

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