Question

1-phenylpropene is treated with $H_{2}O/H^{+}$ The product is :

• A. 1-phenylpropan-1-ol
• B. 2-phenylpropan-1-ol
• C. 1-phenylpropan-2-ol
• D. 2-phenylpropan-1-ol

Answer 1

The correct option is A 1-phenylpropan-1-ol

Addition of $H_{2}O$ to alkene is a Markovnikov addition reaction.

In Markovnikov's addition, negative part of the addendum (adding molecule) gets attached to that doubly bonded C which posses lesser number of hydrogen atoms.

In 1-phenylpropene, the double bond attacks the $H^{+}$ ion and form a secondary phenyl cation. Phenyl carbocation is more stable due to the resonance effect with benzene ring. Now the $O{H}^{-}$ gets added to the carbocation to form 1-phenylpropan-1-ol