$1 L$ of a buffer solution contains one mole each of $C H_{3} C O O H$ & ${(C H_{3} C O O)}_{2} Ba$ . Which of the following options are correct? $(p K_{a} of C H_{3} C O O H = 4.7, log 2 = 0.3)$

pH = 4.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

pH = 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

pOH = 9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

pOH = 9.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
B pH = 5
C pOH = 9
For the given buffer solution $p H$ is given by
$p H = p K_{a} + l o g \frac{[C H_{3} C O O^{-}]}{[C H_{3} C O O H]}$
1 mole of $(C H_{3} C O O)_{2} B a$ will give 2 moles of $C H_{3} C O O^{-}$
$p H = 4.7 + l o g \frac{2}{1}$
$p H = 4.7 + 0.3 = 5$
$p O H = 14 - 5 = 9$

Suggest Corrections

Similar questions

1 L

C H_{3} C O O H

{(C H_{3} C O O)}_{2} Ba

(p K_{a} of C H_{3} C O O H = 4.7, log 2 = 0.3)

50 m l

0.2 M

C H_{3} C O O H

25 m l

C H_{3} C O O N a

4.8

C H_{3} C O O N a

[p K a

C H_{3} C O O H = 4.8]

25^{\circ} C ?

C H_{3} C O O H

C H_{3} C O O N a

p H

N H_{4} O H

N H_{4} C l

Join BYJU'S Learning Program