1L of a buffer solution contains one mole each of CH3COOH & (CH3COO)2Ba. Which of the following options are correct? (pKaofCH3COOH=4.7,log2=0.3)
A
pH = 4.7
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B
pH = 5
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C
pOH = 9
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D
pOH = 9.3
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Solution
The correct option is C pOH = 9 For the given buffer solution pH is given by pH=pKa+log[CH3COO−][CH3COOH]
1 mole of (CH3COO)2Ba will give 2 moles of CH3COO− pH=4.7+log21 pH=4.7+0.3=5 pOH=14−5=9