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Question

(1×103)+(2×102)+(3×100)+(1×101)+(2×102)=

A
123.12
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B
1230.12
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C
1230.21
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D
1230.21
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Solution

The correct option is D 1230.21
Using a0=1 and am=1am,
(1×103)+(2×102)+(3×100)+(1×101)+(2×102)
=1000+200+3+(110)+(2100)
=1000+200+3+0.1+0.02
=1203.12

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