Question

1) Write \(IUPAC\) name of the following:

A)2) Write \(IUPAC\) name of the following:

B) 3) Write \(IUPAC\) name of the following:

(C)
4) Write \(IUPAC\) name of the following:

D)
5) Write \(IUPAC\) name of the following:

E)
6) Write \(IUPAC\) name of the following:

F)

Answer 1

1) If multiple bonds and substituents like \((-X,-NO_{2},-OR~etc.)\) are present, the priority is given to multiple bonds.

Numbering is done in such a way that multiple bonds get lowest possible number.

The parent chain has five carbon atoms.So, its word root is 'pent'.After numbering, the substituent is found as follows:
\(C4:\) bromo

As there is a double bond \(at~C2\), its suffix is 'ene'.

Hence, the \(IUPAC\) name of the given compound is \(4-\text{Bromopent-2-ene}\)

2) If multiple bonds and substituents like \(-X,-NO_{2},-OR~etc.\) are present, the priority is given to multiple bonds.

Numbering is done in such a way that multiple bonds get lowest possible number.

The parent chain has five carbon atoms. So, its word root is 'pent'.After numbering,the substituents are found as follows:
\(C2:\text{methyl}\)
\(C3:\text{bromo}\)

As there is a double bond \(at~C1\),its suffix is 'ene'.The number '1'is used before 'ene'to locate position of double bond.


Hence,the \(IUPAC\) name of the given compound is \(3-\text{Bromo}-2-\text{methylbut}-1-ene.\)

3) If multiple bonds and substituents like \((-X,-NO_{2},-OR~etc.)\) are present, the priority is given to multiple bonds.

Numbering is done in such a way that multiple bonds get lowest possible number.

The parent chain has five carbon atoms. So, its word root is 'pent'.After numbering,the substituents are found as follows:

\(C3:\text{methyl}\)
\(C4:\text{bromo}\)

As there is a double bond \(at~C2\),its suffix is 'ene'.The number '2'is used before 'ene'to locate position of double bond.


Hence,the \(IUPAC\) name of the given compound is \(4-\text{Bromo}-3-\text{methylpent}-2-ene.\)

4) The parent chain has four carbon atoms. So, its word root is 'but'.After numbering,the substituents are found as follows:

\(C1:\text{bromo}\)
\(C2:\text{methyl}\)

As there is a double bond \(at~C2\),its suffix is 'ene'.The number '2'is used before 'ene'to locate position of double bond.


Hence,the \(IUPAC\) name of the given compound is \(1-\text{Bromo}-2-\text{methylbut}-2-ene.\)

5) The parent chain has four carbon atoms. So, its word root is 'but'.After numbering,the substituents are found as follows:

\(C1:\text{bromo}\)

As there is a double bond \(at~C2\),its suffix is 'ene'.The number '2'is used before 'ene'to locate position of double bond.


Hence,the \(IUPAC\) name of the given compound is \(1-\text{Bromobut}-2-ene.\)

6) If multiple bonds and substituents like \(-X,-NO_{2},-OR~etc.\) are present, the priority is given to multiple bonds.

Numbering is done in such a way that multiple bonds get lowest possible number.

The parent chain has three carbon atoms. So, its word root is 'prop'.After numbering,the substituents are found as follows:

\(C2:\text{methyl}\)
\(C3:\text{bromo}\)

As there is a double bond \(at~C1\),its suffix is 'ene'.The number '1' may or may not be used before 'ene'to locate position of double bond.

the substituent are named in alphabetical order in prefix.


Hence, the \(IUPAC\) name of the given compound is \(3-\text{Bromo-2-methylpropene}.\)