Question

$10$ bags of wheat flour each marked 5 kg, actually contained weights of flour (in kg)

$5.05,5.08,5.03,5.00,5.06,5.08,4.98,5.04,5.07,5.00$.

Find the probability of bag chosen at random contains less than $5$ kg.

• A. $\frac{1}{10}$
• B. $\frac{7}{10}$
• C. $\frac{2}{3}$
• D. $0$

Answer 1

The correct option is A $\frac{1}{10}$

Total number of bags $=10$

Number of bags contain flour less than $5kg=1$

$i.e4.98kg$

$P\left(A\right)=\frac{Numberoffavorableoutcomes}{TotalNumberofpossibleoutcomes}$

$\therefore P\left(A\right)=\frac{1}{10}$

Hence option $A$ is correct.