Question

# Eleven bags of wheat flour, each marked 10 kg actually contained the following weights (in kg) of flour: 10.05, 10.20, 10.00, 9.75, 10.00, 10.03, 9.95, 10.35, 9.90, 10.00, 10.08 Find the probability that any of these bags chosen at random contains: (i) more than 10 kg of wheat flour. (ii) less than 9.5 kg of wheat flour.

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Solution

## We have, The total number of bags = 11 (i) As, the number of bags containing more than 10 kg of wheat flour = 5 So, the probability of choosing a bag containing more than 10 kg of wheat flour = $\frac{5}{11}$ (ii) As, the number of bags containing less than 9.5 kg of wheat flour = 0 So, the probability of choosing a bag containing less than 9.5 kg of wheat flour = $\frac{0}{11}$ = 0

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