Question

Eleven bags of wheat flour, each marked 5 kg actually contained the following weights of flour (in kg):

4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 5.08, 4.98, 5.04, 5.07, 5.00,

Find the probability that any of these bags chosen at random more than 5 kg of flour.

Answer 1

Number of total bags (n) =11

No of bags having weight more than 5 kg (m)=7

$\therefore$ Probability P(A) =$\frac{m}{n}=\frac{7}{11}$