10 bags of wheat flour, each marked 5 kg, actually had the following weights-

4.98, 4.9, 5.0, 5.1, 4.5, 5.12, 5.2, 4.89, 4.9, 5.11.

What will be the probability, that any of the bag chosen at random will have more that 5 kg of flour?

0.6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

none of the above.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0.4
We know the formula of probability-

$\frac{N u m b e r o f f a v o u r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s}$

Number of bags which weigh more than 5 kg is 4 (5.1, 5.12, 5.2, 5.11).

Total number of bags are 10.

P(bags weighing more than 5 kg)
= $\frac{4}{10}$ = 0.4

Suggest Corrections

Similar questions

Q. Eleven bags of wheat flour, each marked 5 Kg, actually contained the following weights of flour (in kg):
4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00

Find the probability that any of these bags chosen at random contains more than 5 kg of flour.

Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg):

4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00

Find the probability that any of these bags chosen at random contains more than 5 kg of flour.

Q. Eleven bags of wheat flour, each marked

5 k g

, actually contained the following weights of flour (in kg):

4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00

Find the probability that any of these bags chosen at random contains more than

5 k g

of flour.

Eleven bags of wheat flour, each marked 5 kg actually contained the following weights of flour (in kg):

4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 5.08, 4.98, 5.04, 5.07, 5.00,

Find the probability that any of these bags chosen at random more than 5 kg of flour.

Question 11
Eleven bags of wheat flour, each marked 5kg, actually contained the following weights of flour (in kg):
4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04,5.07, 5.00
Find the probability that any of these bags chosen at random contains more than 5 Kg of flour.

Join BYJU'S Learning Program

10 bags of wheat flour, each marked 5 kg, actually had the following weights- 4.98, 4.9, 5.0, 5.1, 4.5, 5.12, 5.2, 4.89, 4.9, 5.11. What will be the probability, that any of the bag chosen at random will have more that 5 kg of flour?

The correct option is C 0.4We know the formula of probability- Number of favourable outcomesTotal number of outcomes Number of bags which weigh more than 5 kg is 4 (5.1, 5.12, 5.2, 5.11). Total number of bags are 10. P(bags weighing more than 5 kg) = 410 = 0.4

10 bags of wheat flour, each marked 5 kg, actually had the following weights-

4.98, 4.9, 5.0, 5.1, 4.5, 5.12, 5.2, 4.89, 4.9, 5.11.

What will be the probability, that any of the bag chosen at random will have more that 5 kg of flour?