10 balls can be packed in 5 boxes. How many such boxes are required to pack 22 such balls?

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Solution

The correct option is A 11
Consider, $x$ boxes are required.

$\begin{matrix} No. of balls & 10 & 22 No. of boxes & 5 & x \end{matrix}$

The number of boxes and the number of balls are in direct proportion.

$\frac{10}{5} = \frac{22}{x} 10 x = 22 \times 5 x = \frac{22 \times 5}{10} = 11$

$∴$ The 11 boxes are required to pack 22 balls.

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10 balls can be packed in 5 boxes. How many such boxes are required to pack 22 such balls?

The correct option is A 11Consider, x boxes are required. No. of balls1022No. of boxes5x The number of boxes and the number of balls are in direct proportion. 105=22x10x=22×5x=22×510=11 ∴ The 11 boxes are required to pack 22 balls.