CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

10C1+10C3+10C5+10C7+10C9=

A
29
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
210
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2101
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 29
For (X+A)n=Cn0Xn+CnrXnrAr+CnnAn
Put X=1;A=1
Hence, 0=Cn0Cn1+Cn2Cn3 and so on
Cn0+Cn2+Cn4+=Cn1+Cn3+Cn5+ ...(1)
Now put A=1 and we see that
2n=Cn0+Cn1+Cn2+Cn3+Cn4+Cn5+ ...(2)
Hence, the sum of
Cn1+Cn3+Cn5+=2n1 (From (1) and (2))
In the problem, n=10
Hence, answer is 29

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Coefficients of All Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon