10- Calculate half cell potential at 298k for the reaction Zn-2 -Zn if -Zn-2M- Enot Zn-Zn - -0-76V

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Ionization Enthalpy

10. Calculate...

Question

10. Calculate half cell potential at 298k for the reaction Zn\pm +2 ===Zn if [Zn]=2M, Enot Zn\pm /Zn = -0.76V

Open in App

Solution

Suggest Corrections

Similar questions

298 K

Z n^{2 +} + 2 e^{-} \to Z n

[Z n^{2 +}] = 0.1 M

E^{\circ} = - 0.76 v o l t

Z n \to Z n^{2 +} + 2 e^{-} (E_{(Z n^{2 +} / Z n)}^{0} = - 0.76 V)

F e \to F e^{2 +} + 2 e^{-} E^{0} = 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

E^{o}

Z n ⟶ {Z n}^{2 +} + 2 e^{-}

E^{o} = + 0.76 V

F e ⟶ {F e}^{2 +} + 2 e^{-}

E^{o} = + 0.41 V

{F e}^{2 +} + Z n ⟶ {Z n}^{2 +} + F e

E^{o}

Z n \to {Z n}^{2 +} + 2 e^{-}; E^{o} = + 0.76 V

F e \to {F e}^{2 +} + 2 e^{-}; E^{o} = + 0.41 V

{F e}^{2 +} + Z n \to {Z n}^{2 +} + F e

298 K

Z n (s) | Z n_{(e q)}^{2 +} (0.04 M) | | S n_{(e q)}^{2 +} | S n_{(s)} (0.03 M)

E^{\circ} = - 0.76 V, E^{\circ} = - 0.14 V)

Join BYJU'S Learning Program