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Reductions Involving Aldehydes or Ketones

10 g MnO2 on ...

Question

10 g MnO2 on reaction with HCl forms 2.24 L of Cl2[g] at NTP, the percentage impurity of MnO2 is MnO2 + 4HCl - MnCl2 + Cl2 + 2H2O

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M n O_{2} + 4 H C l ⟶ M n C l_{2} + 2 H_{2} O + C l_{2}

2

M n O_{2}

4

H C l

11.2

C l_{2}

at STP. Thus, percent yield of

C l_{2}

0.80

M n O_{2}

146

H C l

react in the following manner:

M n O_{2} + 4 H C l ⟶ M n C l_{2} + C l_{2} + 2 H_{2} O

0.80

M n O_{2}

146

H C l

M n O_{2} + 4 H C l ⟶ M n C l_{2} + C l_{2} + 2 H_{2} O

0.80

M n O_{2}

146

H C l

react, then number of moles of

C l_{2}

formed is (as nearest integer):

M n O_{2} + 4 H C l ⟶ M n C l_{2} + C l_{2} + 2 H_{2} O

M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

1

H C l

1

M n O_{2}

is heated together, the maximum weight of

C l_{2}

gas evolved will be:

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