Question

10g of a Gas at 1atm pressure is cooled from ${273}^{o}C$ to 273K. Keeping its volume constant. The pressure of the Gas will

• A. remain unchanged
• B. becomes 273 atm
• C. 1/273 atm
• D. 0.5atm

Answer 1

The correct option is D

0.5atm

Let the volume be V.

$Now,\frac{P_1}{T_1}=\frac{P_2}{T_2}\therefore P_2=\frac{P_1\times T_2}{T_1}$

$=\frac{1\times 273}{546}=0.5atm$