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Question

A 10 g of a gas at atmospheric pressure is cooled from 273 C to 0 C keeping the volume constant, its pressure would become


A

atm

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B

atm

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C

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D

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Solution

The correct option is A

atm


T1=273C=273+273K=546K

T2=0C=273+0C=273K

P1=1;P2=?

According to Gay-Lussac's law

P1T1=P2T2P2=P1T2T1=1×273K546Katm;12atm.


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