Question

$10\text{g}$ of a gas at atmospheric pressure is cooled from ${273}^{\circ }\text{C}$ to $0^{\circ }\text{C}$ keeping the volume constant. What would be its pressure?

• A. 1/4 atm
• B. remains same
• C. 1/2 atm
• D. 2 atm

Answer 1

The correct option is C 1/2 atm

Given information:
Initial pressure of the gas $P_1=1atm$
Initial temperature of the gas $T_1={273}^{\circ }\text{C}=546K$
Final temperature of the gas $T_2=0^{\circ }\text{C}=273K$
Final Pressure of the gas $P_2=?$
From Gay Lussac's law, $\frac{P_1}{T_1}=\frac{P_2}{T_2}$ at constant volume.

$\frac{1}{546}=\frac{P_2}{273}$

Hence,
$P_2=\frac{1}{2}atm$