Question

$10g$ of hydrogen and $64g$ of oxygen were filled in a steel vessel and exploded. Amount to water produced in this reaction will be:

• A. $3$ mol
• B. $4$ mol
• C. $1$ mol
• D. $2$ mol

Answer 1

Answer: (B)

$4$ mol

$2H_2+O_2\to 2H_{2}O$

10 g of hydrogen (molar mass 2 g/mol) $=\frac{\text{10 g}}{\text{2 g/mol}}=\text{5 mol}$

64 of oxygen (molar mass 32 g/mol) $=\frac{\text{64 g}}{\text{32 g/mol}}=\text{2 mol}$

As per the balanced chemical equation, 1 mole of oxygen will react with $2$ moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with $2\times 2=4$ moles of hydrogen to form $4$ moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.

Hence, option $B$ is correct.