Question

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Volume of gaseous product after reaction is:

• A. $1\times 22.4L$
• B. $2\times 22.4L$
• C. $3\times 22.4L$
• D. $4\times 22.4L$

Answer 1

The correct option is D $4\times 22.4L$

$2H_2+O_2\to 2H_{2}O$

4gm of Hydrogen and 32gm of oxygen combine to form water i.e 1:8

10gm of Hydrogen and 64gm of oxygen combine to form water, then 2gm of Hydrogen is left unreacted.

$\therefore$ volume of gaseous product after reaction is 2gm Hydrogen i.e 1 mole of Hydrogen at STP = 22.4L

Hence, option $A$ is correct.