Question

$10g$ of ice at $0^{o}C$ melts. The entropy then

• A. decreases by $2.93ca{l}^o{C}^{-1}$
• B. increases by $2.93ca{l}^o{C}^{-1}$
• C. remains unchanged
• D. none of these

Answer 1

The correct option is B increases by $2.93ca{l}^o{C}^{-1}$

Enthalpy of fusion of ice is $79.8cal/g$. Thus for $10g$ enthalpy is $798cal/g$.

Thus, we get change in entropy as $\Delta S=\frac{\Delta H}{T}=\frac{798}{273}=2.93cal{/}^{o}C$. It is a positive value, thus entropy increases.