Question

$10$ g of ice is added in $40$ g of water at $15$${}^o$C. The temperature of the mixture is :

• A. 0${}^o$ C
• B. 3${}^o$ C
• C. 12${}^o$ C
• D. 8${}^o$ C

Answer 1

Answer: (A)

0${}^o$ C

Heat require to melt the ice $=$ mL
$=10\times 80$
$=800cal$.
Maximum heat which can be supplied by hot water $=mC\Delta T=40\times 1\times 15=600cal$
As heat supplied < heat required to melt ice.
$\therefore$ temperature of the mixture will be 0${}^o$ C
(as whole of the ice will not melt).